1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Rectangular prism Area=2(wl+hl+hw) in this case, the length (l) is 9m, the width (w) is 8m, the height (h) is 9m. Just plug everything into the formula: 2(8*9+9*9+9*8)=450m^3. Hopefully It helped. Have a good day.
Answer:
148^2
Step-by-step explanation:
2(lb+bh+lh) = 2(4*5+5*6+4*6)=148 in^2
When you line the object up against the ruler you are measuring it's side, if you put it on the one instead of the zero then you're making the object one inch longer, so you'd have to subtract the one in the end
The answer would be 8x^4 + 16x^3y - 48x^2y^2
In order to find this, multiply 8x^2 by each term individually.
8x^2 * x^2 = 8x^4
8x^2 * 2xy = 16 x^3y
8x^2 * -6y^2 = -48x^2y^2
Now you can put them all in a row.
8x^4 + 16x^3y - 48x^2y^2
