Distribute the 3 to get
4x + 2 = 3x-18+8 Then add like terms
4x + 2 = 3x - 10 Now move all x terms to one side by subtracting 3x from both sides
x + 2 = -10. Solve by subtracting 2 from both sides
x = -12
Answer:
The cost of one adult ticket is $8 and cost of one student ticket is $4.
Step-by-step explanation:
Let,
x be the price of one adult ticket
y be the price of one student ticket
According to given statement;
12x+7y=124 Eqn 1
x+3y=20 Eqn 2
Multiplying Eqn 2 by 12
12(x+3y=20)
12x+36y=240 Eqn 3
Subtracting Eqn 1 from Eqn 3
(12x+36y)-(12x+7y)=240-124
12x+36y-12x-7y=116
29y=116
Dividing both sides by 29
Putting y=4 in Eqn 2
x+3(4)=20
x+12=20
x=20-12
x=8
Hence,
The cost of one adult ticket is $8 and cost of one student ticket is $4.
You just have to multiply 48 by 4 to find out its original price