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swat32
3 years ago
10

What is equivalent to 17g-2g

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0
15g

if you had 17 dollars and gave away two dollars you'd have 15 dollars left. Samer if you have 2g's, whatever those are:)
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What is 1.208 rounded to the nearest hundredth
rusak2 [61]

Answer:

The answer is 1.21.

Step-by-step explanation:

The hundredth digit in 1.208 is 0, so you have to look at the number after that to either round 0 up or down. The number after 0 is 8. Since 8 is bigger than 5, you round 0 up by 1.


I hope this was clear!

5 0
3 years ago
In a class of 6, there are 2 students who forgot their lunch.
lukranit [14]

Answer:

1/8

Step-by-step explanation:

AB,AA,BB,BB,BB,BB,BB,BB,

*A IS THE students that forgot thier lunch

4 0
3 years ago
I need help is it A B C or D
Evgesh-ka [11]
Y=12/x
12/2=6
12/4=3
12/8=1.5 or 3/2
12/12=1
Answer is b
4 0
4 years ago
a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1
Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

\text {volume of cylinder }=\pi r^{2} h

Where "r" is the radius of cylinder

"h" is the height of cylinder and \pi is constant has value 3.14

Substituting the values in formula, we get

\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}

Taking square root on both sides,

r = \sqrt{4}\\\\r = 2

Thus the radius of the container is 2 centimeter

4 0
3 years ago
Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.
Yakvenalex [24]

Answer: x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

Step-by-step explanation:

2x^2-9x+5

a=2

b=-9

c=5

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)}  }{2(2)}

x=\frac{9\frac{+}{}\sqrt{81-40}  }{4}

x=\frac{9\frac{+}{}\sqrt{41}  }{4}

x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

4 0
3 years ago
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