I will be giving brainliest
2 answers:
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Answer:
<u>All the four statements are true , which are -</u>
(A) The subset contains contains of all the outfits that have grey slacks .
(B) The subset contains contains of all the outfits that have grey slacks and red tie .
(C) The subset contains contains of all the outfits that have grey slacks and blue shirt .
(D) The subset contains contains of all the outfits that do not have black slacks .
Step-by-step explanation:
<u>We are given with Outfit 2 , 4 and 6</u>
Outfit 2 - Blue grey red
Outfit 4 - White grey red
Outfit 6 - Black grey red
(A) Since only 2,4, and 6 contain grey slacks, and no other outfit contains grey slacks, those are the subsets that contain grey slacks. Thus , this statement is true .
(B) Just outfits 2, 4, and 6 have grey slacks and a red tie, proving the statement. Other clothes do not include grey slacks and a red tie; they may include a red tie but not both grey slacks and a red tie. Hence , the statement is true .
(C) Since the outfit 2 has grey slacks and a blue shirt, the statement is correct; no other outfit has both grey slacks and a blue shirt. Therefore , this statement is also correct .
(D) The argument is correct since all of the subsets contain grey slacks and no black slacks.
Hence , all the options A , B , C , D are correct and describes the subset .
<u>The given question is incomplete , the complete question is attached here - </u>
I found the missing parts of this question.
Test A
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>
<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>
<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>
Refer to the attachment for the formula of z score:
test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2
B. <span>Test A: –3; Test B: –2; Test B </span>
Test A
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>
<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>
<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>
Refer to the attachment for the formula of z score:
test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2
B. <span>Test A: –3; Test B: –2; Test B </span>