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3 years ago

2-8 Examine the function h(x) defined at right. Then estimate the values Below.

Mathematics

1 answer:

Arada [10]3 years ago

5 0

We are given graph of the function.

Let us do given parts one by one.

a) h(1).

Here, we need to find the value of function (y-coordinate) for x=1.

From the given graph, we can see the for x=1 value of y is 2.

Therefore, h(1)=2.

b) h(3).

Here, we need to find the value of function (y-coordinate) for x=3.

From the given graph, we can see the for x=3 value of y is -4.

Therefore, h(3)=-4.

c) x when h(x) =0.

Here, we need to find the value of x-coordinate for y=0.

From the given graph, we can see the for y=0 value of x is also 0.

Therefore, x=0 when h(x)=0.

d) h(-1).

Here, we need to find the value of function (y-coordinate) for x=-1.

From the given graph, we can see the for x=-1 value of y is -2.

Therefore, h(-1)=-2.

e) h(-4).

Here, we need to find the value of function (y-coordinate) for x=-4.

From the given graph, we can see the for x=-4 value of y is 13.

Therefore, h(-4)=13.

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The perimeter of a square is 30cm the perimeter of a rectangle is 30cm use this information to find out the area of the square b

kogti [31]

Step-by-step explanation:

perimeter of square = 30cm

perimeter of rectangle = 30cm

area of square is = 30×30= 900 cm

hope it helps , make sure to follow !!!!

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3 years ago

The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions

Salsk061 [2.6K]

Width = 5.5yd

Length = 12yd

Explanation:

Area of rectangle = $66yd^{2}$

Let width of the rectangle = b ,

So, length = 2b+1

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

$66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\$

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,

Width = 5.5yd

Length = 12yd

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3 years ago

Asap asap pls help no idea will mark brainliest !

blondinia [14]

Answer:

I think that the area is 165 km squared. Please forgive me if im wrong!!!

Step-by-step explanation:

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3 years ago

Graph the linear function using slope intercept form y=2x+6

Stella [2.4K]

Start in the middle and go up 6 then draw a dot, after that you go up two and right one and do it all the way you can and then to go the opposite way go down two and left one. Hope this helps

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3 years ago

Read 2 more answers

3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it

Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

(e) Using Mathematica, the roots are found to be as shown in the second attachment. The highest root is about ...

... x ≈ 3.0466805180

_____

Comment on these methods

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0

3 years ago