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bixtya [17]
3 years ago
11

2-8 Examine the function h(x) defined at right. Then estimate the values Below.

Mathematics
1 answer:
Arada [10]3 years ago
5 0

We are given graph of the function.

Let us do given parts one by one.

a) h(1).

Here, we need to find the value of function (y-coordinate) for x=1.

From the given graph, we can see the for x=1 value of y is 2.

Therefore, h(1)=2.

b) h(3).

Here, we need to find the value of function (y-coordinate) for x=3.

From the given graph, we can see the for x=3 value of y is -4.

Therefore, h(3)=-4.

c) x when h(x) =0.

Here, we need to find the value of x-coordinate for y=0.

From the given graph, we can see the for y=0 value of x is also 0.

Therefore, x=0 when h(x)=0.

d) h(-1).

Here, we need to find the value of function (y-coordinate) for x=-1.

From the given graph, we can see the for x=-1 value of y is -2.

Therefore, h(-1)=-2.  

e) h(-4).

Here, we need to find the value of function (y-coordinate) for x=-4.

From the given graph, we can see the for x=-4 value of y is 13.

Therefore, h(-4)=13.  

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Suppose that nine is a factor of a number which statement has to be true
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Read 2 more answers
<img src="https://tex.z-dn.net/?f=12x%20%5E%7B2%7D%20%20%2B%204x%20%2B%2020" id="TexFormula1" title="12x ^{2} + 4x + 20" alt="1
Nesterboy [21]
<h3>Answer: </h3>

The GCF is 4

The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

  • 12 = 2*2*3
  • 4 = 2*2
  • 20 = 2*2*5

Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

12x^2 + 4x + 20\\\\4*3x^2 + 4*x + 4*5\\\\4(3x^2 + x + 5)

The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

4 0
2 years ago
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