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AlladinOne [14]
3 years ago
14

Where is the removable discontinuity of f(x) located? x = -5 F(x)=5x+10/x^2+7x+10

Mathematics
2 answers:
stiks02 [169]3 years ago
4 0
The discontinuity of f(x) is at x=25. The denominator goes to zero.
zvonat [6]3 years ago
3 0

Answer:

F(x)=0

Step-by-step explanation:

5x+10/x^2+7x+10

When x=-5

Substitute the value of x in the equation

5(-5)+10/(-5^2+7(-5)+10

-25+10/25-35+10

-15/-10+10

-15/0

=0

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