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3 years ago

Where is the removable discontinuity of f(x) located? x = -5 F(x)=5x+10/x^2+7x+10

Mathematics

2 answers:

stiks02 [169]3 years ago

4 0

The discontinuity of f(x) is at x=25. The denominator goes to zero.

zvonat [6]3 years ago

3 0

Answer:

F(x)=0

Step-by-step explanation:

5x+10/x^2+7x+10

When x=-5

Substitute the value of x in the equation

5(-5)+10/(-5^2+7(-5)+10

-25+10/25-35+10

-15/-10+10

-15/0

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Since we have given that

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