Where is the removable discontinuity of f(x) located? x = -5 F(x)=5x+10/x^2+7x+10
2 answers:
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Answer:
The graph shifts 7 units left and 2 units up.
Step-by-step explanation:
In transformations, when a number is added or subtracted to "x" directly, that is the left/right shift.
When a number is added or subtracted outside of the "rest" of the equation, that is the up/down shift.
I learned transformations with these variables:
"a" - vertical stretch (a > 1) or compression (0 < a < 1)
"k" - horizontal stretch (0 < k < 1) or compression (k > 1)
"c" - translate left (+) or right (-)
"d" - translation up (+) or down (-)
The untranslated graph is centred around the origin f(x) = 1/x
f(x) begins 3 units right and 1 unit up of the untranslated graph.
g(x) is 4 units left and 3 units up of the untranslated graph.
y
g |
| f
-----------|------------ x
There is a 7 units translation left and 2 units translation up.