Answer:
scalene
Step-by-step explanation:
all 3 sides are different lengths
i cannot see a right angle
Part of the value of sin(u) is cut off; I suspect it should be either sin(u) = -5/13 or sin(u) = -12/13, since (5, 12, 13) is a Pythagorean triple. I'll assume -5/13.
Expand the tan expression using the angle sum identities for sin and cos :
tan(u + v) = sin(u + v) / cos(u + v)
tan(u + v) = [sin(u) cos(v) + cos(u) sin(v)] / [cos(u) cos(v) - sin(u) sin(v)]
Since both u and v are in Quadrant III, we know that each of sin(u), cos(u), sin(v), and cos(v) are negative.
Recall that for all x,
cos²(x) + sin²(x) = 1
and it follows that
cos(u) = - √(1 - sin²(u)) = -12/13
sin(v) = - √(1 - cos²(v)) = -3/5
Then putting everything together, we have
tan(u + v)
= [(-5/13) • (-4/5) + (-12/13) • (-3/5)] / [(-12/13) • (-4/5) - (-5/13) • (-3/5)]
= 56/33
(or, if sin(u) = -12/13, then tan(u + v) = -63/16)
In the triangle ABE
step 1
Find out the measure of angle AEB
m by form a linear pair
mm
step 2
Find out the measure of angle ABE
m by alternate interior angles
step 3
Find out the measure of angle x
Remember that
The sum of the interior angles in any triangle must be equal to 180 degrees
so
msubstitute given values
x+100+30=180
x=180-130
<h2>x=50 degrees</h2>
Given :
Two similar triangle.
To Find :
The ratio of the area of triangle abc to the area of triangle edc.
Solution :
ΔABC ~ ΔAPQ (AA criterion for similar triangles)
Since both the triangles are similar, using the theorem for areas of similar triangles we have :
Therefore, ratio of area of triangle is 1.4 .