Determine if each table shown below represents a function or not ?

Mathematics

2 answers:

Sladkaya [172]3 years ago

6 0

Answer: neither of the examples are functions

Step-by-step explanation:

To be a function, every x-value must be associated to only one y-value. In the first table x= 5 maps to TWO y values.

In the second table, x=7 maps to TWO y values

yarga [219]3 years ago

5 0

Neither of them are functions. Functions cannot have two of the same numbers in the x value, and since the first table has two 5s in the x column and the second table has two 7s, neither of them can be functions.

Hope this helps :)

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Ne4ueva [31]

Answer: I'm not sure if this is right or not but I got U = 4

Step-by-step explanation: -8(2v-2)=-4(7+5u. So first I distributed and got -16v -16 = 28 + 20u. And then I added 16u with 20u I added because you change the sign like if it's a negative you make it a positive so once you do 20u+16v you should get 36 and then on the other side it should be -16+16 which equals -16u from when you distributed so now you should have -16u=28+36 so now you would add 28 the 36 since they both are positives and have no variables which you should get 64 and then on the left you should have 16u. So it looks like -16u=64. And then now you would divide -16u on both sides and the side with the variable put it or v whatever variable you want to use and then do 64 divided by 16 and you should get 4.

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3 years ago

What is the growth rate for 3x-y=8x-7

nydimaria [60]

Answer:

you mean like this :))

-5x +7 = Y

Step-by-step explanation:

3x - y = 8x - 7

<=>3x - 8x = y - 7

<=>-5x = y - 7

<=>-5x + 7 = Y