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maxonik [38]
3 years ago
10

Pls help I will mark brainliest

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0

Answer:

A. 60 Degrees

Step-by-step explanation:

If i understand this correctly, you take the number of sides that are identically and put a one over it to make a fraction.

<em>1/6</em>

then you multiply by 360 degrees

<em>(1/6)  * 360 = 60</em>

enot [183]3 years ago
5 0

A 60 degrees

I hope this helps!

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Step-by-step explanation:

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Assume the amount you can spend on car payments is 50% of your monthly surplus.
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Which set of ordered pairs represents a function? (1 point) {(0, 1), (1, 3), (1, 5), (2, 8)} {(0, 0), (1, 2), (2, 6), (2, 8)} {(
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Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

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z_{\alpha/2}=1.96

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And replacing we got:

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And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

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3 years ago
15. A cylindrical glass 10 cm tall and 8 cm in diameter is filled to 1 cm
ANTONII [103]

Answer:

No. The new height of the water is less than the height of the glass(6.33 cm<10 cm)

Step-by-step explanation:

-For the water in the glass to overflow, the volume of the inserted solid must be greater than the volume of the empty space or the ensuing height of  water >height of glass.

#Volume of the golf ball:

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#The volume of the water in the glass:

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V=\pi r^2h\\\\(206.08+50.27)=\pi r^2 h\\\\h=318.35/(\pi \times 4^2)\\\\=6.33\ cm

Hence, the glass will not overflow since the new height of the water is less than the height of the glass(6.33 cm<10cm).

4 0
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