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solmaris [256]
3 years ago
13

How to do quadratic equations

Mathematics
2 answers:
VikaD [51]3 years ago
7 0

Answer:

f(x)= \frac{-b+\sqrt{b^{2}-4ac } }{2a}

Step-by-step explanation:

the plus sign is actually a plus or minus

Paraphin [41]3 years ago
5 0

Step-by-step explanation:

READ SLOWLY TO UNDERSTAND

Factoring

To solve a quadratic equation by factoring,

Put all terms on one side of the equal sign, leaving zero on the other side.

Factor.

Set each factor equal to zero.

Solve each of these equations.

Check by inserting your answer in the original equation.

Example 1

Solve x 2 – 6 x = 16.

Following the steps,

x 2 – 6 x = 16 becomes x 2 – 6 x – 16 = 0

Factor.

( x – 8)( x + 2) = 0

Setting each factor to zero, equation

Then to check, equation

Both values, 8 and –2, are solutions to the original equation.

Example 2

Solve y 2 = – 6 y – 5.

Setting all terms equal to zero,

y 2 + 6 y + 5 = 0

Factor.

( y + 5)( y + 1) = 0

Setting each factor to 0, equation

To check, y 2 = –6 y – 5

equation

A quadratic with a term missing is called an incomplete quadratic (as long as the ax 2 term isn't missing).

Example 3

Solve x 2 – 16 = 0.

Factor.

equation

To check, x 2 – 16 = 0

equation

Example 4

Solve x 2 + 6 x = 0.

Factor.

equation

To check, x 2 + 6 x = 0

equation

Example 5

Solve 2 x 2 + 2 x – 1 = x 2 + 6 x – 5.

First, simplify by putting all terms on one side and combining like terms.

equation

Now, factor.

equation

To check, 2 x 2 + 2 x – 1 = x 2 + 6 x – 5

equation

The quadratic formula

Many quadratic equations cannot be solved by factoring. This is generally true when the roots, or answers, are not rational numbers. A second method of solving quadratic equations involves the use of the following formula: equation

a, b, and c are taken from the quadratic equation written in its general form of

ax 2 + bx + c = 0

where a is the numeral that goes in front of x 2, b is the numeral that goes in front of x, and c is the numeral with no variable next to it (a.k.a., “the constant”).

When using the quadratic formula, you should be aware of three possibilities. These three possibilities are distinguished by a part of the formula called the discriminant. The discriminant is the value under the radical sign, b 2 – 4 ac. A quadratic equation with real numbers as coefficients can have the following:

Two different real roots if the discriminant b 2 – 4 ac is a positive number.

One real root if the discriminant b 2 – 4 ac is equal to 0.

No real root if the discriminant b 2 – 4 ac is a negative number.

Example 6

Solve for x: x 2 – 5 x = –6.

Setting all terms equal to 0,

x 2 – 5 x + 6 = 0

Then substitute 1 (which is understood to be in front of the x 2), –5, and 6 for a, b, and c, respectively, in the quadratic formula and simplify.

equation

Because the discriminant b 2 – 4 ac is positive, you get two different real roots.

Example produces rational roots. In Example , the quadratic formula is used to solve an equation whose roots are not rational.

Example 7

Solve for y: y 2 = –2y + 2.

Setting all terms equal to 0,

y 2 + 2 y – 2 = 0

Then substitute 1, 2, and –2 for a, b, and c, respectively, in the quadratic formula and simplify.

equation

Note that the two roots are irrational.

Example 8

Solve for x: x 2 + 2 x + 1 = 0.

Substituting in the quadratic formula,

equation

Since the discriminant b 2 – 4 ac is 0, the equation has one root.

The quadratic formula can also be used to solve quadratic equations whose roots are imaginary numbers, that is, they have no solution in the real number system.

Example 9

Solve for x: x( x + 2) + 2 = 0, or x 2 + 2 x + 2 = 0.

Substituting in the quadratic formula,

equation

Since the discriminant b 2 – 4 ac is negative, this equation has no solution in the real number system.

But if you were to express the solution using imaginary numbers, the solutions would be equation.

Completing the square

A third method of solving quadratic equations that works with both real and imaginary roots is called completing the square.

Put the equation into the form ax 2 + bx = – c.

Make sure that a = 1 (if a ≠ 1, multiply through the equation by equation before proceeding).

Using the value of b from this new equation, add equation to both sides of the equation to form a perfect square on the left side of the equation.

Find the square root of both sides of the equation.

Solve the resulting equation.

Example 10

Solve for x: x 2 – 6 x + 5 = 0.

Arrange in the form of

equation

Because a = 1, add equation, or 9, to both sides to complete the square.

equation

Take the square root of both sides.

x – 3 = ±2

Solve.

equation

Example 11

Solve for y: y 2+ 2 y – 4 = 0.

Arrange in the form of

equation

Because a = 1, add equation, or 1, to both sides to complete the square.

equation

Take the square root of both sides.

equation

Solve.

equation

Example 12

Solve for x: 2 x 2 + 3 x + 2 = 0.

Arrange in the form of

equation

Because a ≠ 1, multiply through the equation by equation.

equation

Add equation or equation to both sides.

equation

Take the square root of both sides.

equation

There is no solution in the real number system. It may interest you to know that the completing the square process for solving quadratic equations was used on the equation ax 2 + bx + c = 0 to derive the quadratic formula.

You might be interested in
I need help with my math
Nat2105 [25]

Answer:

Part A. C=9

Part B. (w+3)² =139

Part C. w = 8.8 inch

Step-by-step explanation:

Given from the question length of the the picture = (2w+12) inches

Width of the picture = w inches

Area of the picture = 260 inch²

Part A. Area of the picture with the given dimensions= w×(2w+12)

Or w(2w+12) = 260

2w²+12w = 260

2(w²+6w) = 2×(130)

w²+6w = 130

Or w²+6w +9 = 130+9 ⇒ which is in the form of w²+6w+c = 130+c

Therefore for c = 9 we will get a perfect square trinomial.

Part B. As we have seen the equation in part A.

As required equation will be (w+3)²=139

Part C. Since (w+3)² = 139

Then by taking under root on both the sides of the equation

(w+3) =√139 = 11.8

(w+3)-3=11.8-3

w = 8.8 inch

3 0
3 years ago
5/9 4.9 meters tall ratio
Keith_Richards [23]
5 + 9 = 14

4.9 / 14 = 0.35

0.35 * 5 = 1.75

0.35 * 9 = 3.15

The answer is 1.75 / 3.75
8 0
3 years ago
What is the value of the expression |-7| + |-4|
weqwewe [10]
Hey there,

Your question states: <span>What is the value of the expression |-7| + |-4|

Sense they both are absolute values, they are pretended to be as normal numbers. By simplifying this, your correct answer would be 11.

Hope this helps.
~Jurgen</span>
7 0
3 years ago
WILL GIVE BRAINLIEST
ivanzaharov [21]
\frac{3x^3+9x^2-6x}{-3x}
Since the denominator is a monomial, we divide each term of the trinomial in the numerator by the denominator.
\frac{3x^3}{-3x} = -1x^2, because 3/-3 = 1 and x³/x = x².
\frac{9x^2}{-3x}=-3x; 9/-3 = -3 and x²/x = x.
\frac{-6x}{-3x} = 2; -6/-3 = 2 and x/x = 1, so we have 2*1  = 2.
Together this gives us -x^2-3x+2
7 0
4 years ago
What is the volume of the triangular prism and help me fill it in
dlinn [17]

Answer:

V = B x h

V =( (1/2) x 6 x 8 ) x h

V = 24 x 14

V = 336

=> The volume is 336

7 0
3 years ago
Read 2 more answers
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