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3 years ago

What is 56 decreased by twice a number

Mathematics

2 answers:

DerKrebs [107]3 years ago

7 0

Algebraic expresion: 56-2x

Mnenie [13.5K]3 years ago

7 0

2x-56. This is the answer because since you don't know what the number is it is gonna be x and twice a number would be 2x. The 56 is subtracted from the 2x because decreased means subtraction.

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Can u help solve this W-5=5

leonid [27]

W-5=5
W= 5+5 (bringing -5 to the other side, it becomes +5)
At last, W=10.

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3 years ago

I WILL GIVE BARINLEST WHO HELP ME<br><br>3

Pavlova-9 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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If f(x)= 2x+5 and g(x)= 3x2 +2x+5, what is f(3)+g(2)?

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

1. find f(3) = 2x + 5

a) y = 2(3) + 5

b) y = 6 + 5

c) y = 11

2. find g(2) = 3x² + 2x + 5

a) y = 3(2)² + 2(2) + 5

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c) y = 12 + 4 + 5

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3 years ago

A number increased by 19 is the same as 9 less than five times a number

IgorLugansk [536]

Answer:

the number should be 7

Step-by-step explanation:

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3 years ago

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Chemists use pH as a measure of acidity or alkalinity of a solution. It uses the concentration of hydrogen ions H+ in a logarith

SpyIntel [72]

Answer:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Step-by-step explanation:

Given

$f(d) = (0.5 * 10^{-4})^d$

$g(H+) = -log_{10}(H+)$

Required

Find the composite function g(f(d))

We have:

$g(H+) = -log_{10}(H+)$

Substitute f(d) for H+

$g(f(d)) = -log_{10}(f(d))$

Substitute $f(d) = (0.5 * 10^{-4})^d$

$g(f(d)) = -log_{10}((0.5 * 10^{-4})^d)$

Apply law of logarithm

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Hence, the function is:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

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2 years ago

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