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vazorg [7]
3 years ago
8

What polynomial can be factored as (a+6)(a+3) ?​

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

a²+9a+18

Step-by-step explanation:

axa+ax3+6xa+6x3

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Any other answers to this question?
oksano4ka [1.4K]

Answer:

yes the answer is the answer that you need lol thx

hope it helped :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Write and solve an equation to find the unknown side length x (in inches). Perimeter =24.2 in. Sides of the shape are 8.3, 8.3,
Anastasy [175]

Answer:

Perimeter of shape,which is a convex polygon i.e quadrilateral = 24.2 in

Sides are 8.3 in, 8.3 in, 3.8 in ,and length of fourth side be x in.

As , Perimeter = Sum of all sides

                 → 24.2 = 8.3 + 8.3 + 3.8 + x

                 → 24.2 = 16.6 +3.8 + x

                 → 24.2 = 20 .4 + x

Keeping like terms on one side, of equation

            → 24.2 - 20.4 = x

            → 3.8 = x

            → x = 3.8

So, length of fourth side = 3.8 in

The given shape is definately either a Parallelogram or a kite.



7 0
4 years ago
Find the missing numbers.
irinina [24]
Answers

1. 6
2. 1
3. 4
5 0
3 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
If this fish tank is filled only halfway, how much water will it hold?
Morgarella [4.7K]

Answer:

I believe you typed your final answer choice incorrectly, as it should read 960 which is the correct answer

Step-by-step explanation:

the volume is 1920

1920/2=960

6 0
3 years ago
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