Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Easy, find the equation of the line,
Using y=mx+b form:
(-1,3) m=2
3= 2(-1)+b
3= -2+b
+2 +2
5=b
y=2x+5. This is your equation.
Now, plug in the coordinates:
(-3,2)
2= 2(-3)+5
2= -6+5
2= -1
NO
(0,5)
5= 2(0)+5
5=5
YES
(1,5)
5= 2(1)+5
5= 2+5
5=7
NO
(1,4)
4= 2(1)+5
4= 2+5
4=7
NO.
Thus, B, is your answer.
Answer:
Point d
Step-by-step explanation:
because the x is -2 and the y is 3 so you look for the x and then the y
it would be 7 lolz dheisns
