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vazorg [7]
3 years ago
13

Susan paid $240 to have her house decorated. The materials used to decorate the house coast $115, and service was charged at $5

an hour. How many hours was the house worked on?
Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

240 =5x +115

And we can solve for x in order to find the number hours using to decorate the house.

We can subtract in both sides 115 and we got:

240-115= 5x

125 = 5x

And now we can divide both sides by 5 and we got:

x= 25

So then the number of hours spent to decorate the house are 25

Step-by-step explanation:

Based on the information given we can model this function with this formula:

y = mx+b

Where y represent the total cost paid, m the cost per hour representing the slope and x the number of hours worked and finally b the initial cost for the materials. Then our function is given by:

240 =5x +115

And we can solve for x in order to find the number hours using to decorate the house.

We can subtract in both sides 115 and we got:

240-115= 5x

125 = 5x

And now we can divide both sides by 5 and we got:

x= 25

So then the number of hours spent to decorate the house are 25

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Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

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The mean and the standard deviation are given, respectively, by:

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The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

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Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

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