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Paraphin [41]
3 years ago
9

(sinx-1)(sinx+cos^2x) multiply and simplify

Mathematics
1 answer:
sveta [45]3 years ago
7 0
\bf [sin(x)-1][sin(x)+cos^2(x)]\\\\
-------------------------------\\\\
sin^2(x)+sin(x)cos^2(x)-sin(x)-cos^2(x)
\\\\\\\
[sin^2(x)-cos^2(x)]+[sin(x)cos^2(x)-sin(x)]
\\\\\\
-[cos^2(x)-sin^2(x)]-[sin(x)-sin(x)cos^2(x)]
\\\\\\
-[\stackrel{cos(2x)}{cos^2(x)-sin^2(x)}]-sin(x)\stackrel{sin^2(x)}{[1-cos^2(x)]}
\\\\\\
-cos(2x)-sin(x)sin^2(x)\implies -cos(2x)-sin^3(x)
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Can the sides of a triangle have lengths 3.5, 10.9, and 14.4?
andrew11 [14]

Answer:

No

Step-by-step explanation:

A triangle can NOT have those lengths because any side of a triangle has to have a length greater than the sum of the other two sides. In this case, 14.4, one of the sides, is not greater than the sum of the other two sides (which is also 14.4).

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4 0
2 years ago
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serious [3.7K]

Answer:


1. y = 1/4 and y = 1/4x+2

2. y - 1 = -x (x + 7) and y = -x and x + y = 3

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4. y = 3 and x = 6

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4 0
3 years ago
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2 years ago
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3 years ago
A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random v
Dima020 [189]

Answer: 2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

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6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

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Then add them all together to find the μ

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2 years ago
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