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Paraphin [41]
3 years ago
9

(sinx-1)(sinx+cos^2x) multiply and simplify

Mathematics
1 answer:
sveta [45]3 years ago
7 0
\bf [sin(x)-1][sin(x)+cos^2(x)]\\\\
-------------------------------\\\\
sin^2(x)+sin(x)cos^2(x)-sin(x)-cos^2(x)
\\\\\\\
[sin^2(x)-cos^2(x)]+[sin(x)cos^2(x)-sin(x)]
\\\\\\
-[cos^2(x)-sin^2(x)]-[sin(x)-sin(x)cos^2(x)]
\\\\\\
-[\stackrel{cos(2x)}{cos^2(x)-sin^2(x)}]-sin(x)\stackrel{sin^2(x)}{[1-cos^2(x)]}
\\\\\\
-cos(2x)-sin(x)sin^2(x)\implies -cos(2x)-sin^3(x)
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CCSS Math 7
Andre45 [30]

Answer:

1.

a = 112

b = 68

c = 68

2.

a = 127

3.

a=35

b=40

c=35

d=70

4.

a= 30

b=70

c = 30

d=70

e = 130

I'll help you with the rest later

Step-by-step explanation:

a = 112 because of allied angles rule

b and c = 68 because of angles at a point

360-112-112 ÷2

2. a = 127 because of angles on a straight line rule.

180-38-15

3. d= 70, vertically opposite angle

using angles on a straight line, 180 - 70 - 40 ÷ 2

we now have the two angles and because they are vertically opposite a and c = 35

b = 40 because of vertically opposite angles

4. a=30 because 90-70

since a=30, take 90 - 30 to get b, 70

d= 70, vertically opposite angles

e = 130 because a+b+c, vertically opposite angles

7 0
2 years ago
an item is regularly priced at $45. it is on sale for 40% off the regular price. how much (in dollars) is discounted from the re
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Answer:

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