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aalyn [17]
3 years ago
7

Victoria has two $ 20 bill in her wallet. She spent $ 12.25 on a gift and $ 5.25 on wrapping paper. How much money does Victoria

have left?
A : $ 2.50
B : $ 17.50
C : $ 22.50
D : $ 27.75
Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

The answer is option C. Two $20 bills is $40 altogether. If you subtract Victoria’s purchases ($12.25 and $5.25) from $40, you are left with $22.50.

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Elenna [48]

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Answer:

  $0.50/lb

Step-by-step explanation:

The increase in cost is $40-25 = $15 for an increase in weight of 50-20 = 30 lb. That makes the cost per pound be ...

  cost/pounds = $15/(30 lb) = $0.50/lb

6 0
3 years ago
Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
3 years ago
It also detects if you are right or wrong
Sindrei [870]

Answer:

I think A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

8 0
4 years ago
Consider the following scenario describing Mr. Smith's math students: A list pairs math grades with student heights.
KonstantinChe [14]

Answer:

No, Because students who have the same math grade can be different heights

Step-by-step explanation:

C is the answer DO NOT PICK D

You have the put the correct input and output IN ORDER so D is the wrong answer

8 0
3 years ago
Read 2 more answers
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