What is the value of e in e^x
1 answer:
You might be interested in
Answer:
The proof is derived from the summarily following equations;
∠FBE + ∠EBD = ∠CBA + ∠CBD
∠FBE + ∠EBD = ∠FBD
∠CBA + ∠CBD = ∠ABD
Therefore;
∠ABD ≅ ∠FBD
Step-by-step explanation:
The two column proof is given as follows;
Statement Reason
bisects ∠CBE
Given
Therefore;
∠EBD ≅ ∠CBD Definition of angle bisector
∠FBE ≅ ∠CBA Vertically opposite angles are congruent
Therefore, we have;
∠FBE + ∠EBD = ∠CBA + ∠CBD Transitive property
∠FBE + ∠EBD = ∠FBD Angle addition postulate
∠CBA + ∠CBD = ∠ABD Angle addition postulate
Therefore;
∠ABD ≅ ∠FBD Transitive property.