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mixas84 [53]
3 years ago
6

suppose there were 2 types of tickets to a show . advanced and same day adviced cost $30 . same day $25. for 1 performance 45 ti

ckets were sold on all . the ticket amount paid for them was $1275. how many tickets were sold for advanced? and how many for same day
Mathematics
1 answer:
VikaD [51]3 years ago
7 0

30 x 30 + 25 x 15 = $1275

So,
30 tickets were sold from the $30 type, while 15 tickets were sold from the $25 type!

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Okay so essentially the a_n is just a substitute for x.

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y=a_n\\m=2\\n=x\\b=13

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y=mx+b\\a_n=2n+13\\a_1=2(1)+13=15\\a_2=2(2)+13=17\\a_3=2(3)+13=19\\a_4=2(4)+13=21\\a_5=2(5) +13=23\\a_6=2(6)+13=25\\a_7=2(7)+13=27\\a_8=2(8) +13=29\\a_9=2(9)+13=31\\a_{10}=2(10)+13=33\\a_{11}=2(11)+13=35\\a_{12}=2(12)+13=37\\a_{13}=2(13)+13=39

These are all the answers leading up to the 13th term they asked for, and you can continue thus same equation with whatever number you can put into the n space.

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