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Westkost [7]
3 years ago
9

Factor and then solve the question. X^2-6X=7​

Mathematics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

The solution set is {-1, 7}.

Step-by-step explanation:

X^2-6X=7​

X^2 - 6X - 7​ = 0

(X - 7)(X + 1) = 0

X = 7, -1.

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In an experiment, it is important that independent and dependent variables are given _____, which specify procedures for manipul
Nata [24]

Answer:

a relationship ( model equation)

Step-by-step explanation:

the relationship specifies how the dependent variable relies on the independent variable.This helps in manipulating of the variable to see its effect/outcome.The relationship can be mathematical or logical ; it can also be a set of algorithm (program) which can be worked on using the independent variables as inputs. Usually the independent variables influence the dependent variables.

3 0
4 years ago
HELP PLEASE!!! 50 POINTS INCORRECT ANSWERS WILL BE REPORTED.
Katena32 [7]
Congruent means same so the equation is
5x+24=9x-17
Subtract 5x on both sides
24=4x-17
Add 17 to both sides
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5 0
3 years ago
5x − 3+ 2x = x + 7 + 6x
Masteriza [31]

Answer:

There isnt any solution.

Step-by-step explanation:

but these are the steps:

Step 1: Simplify both sides of the equation.

5x−3+2x=x+7+6x

5x+−3+2x=x+7+6x

(5x+2x)+(−3)=(x+6x)+(7)

7x+−3=7x+7

7x−3=7x+7

Step 2: Subtract 7x from both sides.

7x−3−7x=7x+7−7x

−3=7

Step 3: Add 3 to both sides.

−3+3=7+3

0=10

<h3>hope this helps</h3>

7 0
4 years ago
Factor x^2-8x-48 completely
Naddik [55]

Answer: (X-12)(x+4)

The middle number is -8 and the last number is -48.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -8

Multiply together to get -48

Can you think of the two numbers?

Try 4 and -12:

4+-12 = -8

4*-12 = -48

Fill in the blanks in

(x+_)(x+_)

with 4 and -12 to get...

(x+4)(x-12)

Answer:

(x+4)(x−12)

6 0
3 years ago
Read 2 more answers
What is 4/3 divided by 5/2
Anna [14]
<h2>4/3 divided by 5/2</h2>

<h3>=  \tt{ \dfrac{ \dfrac{4}{3} }{ \dfrac{5}{2} } }</h3><h3>=  \tt{ \dfrac{ \dfrac{4}{15} }{2} }</h3><h2>= \green{\boxed{\tt{{ \dfrac{2}{15} }}}}</h2>
3 0
3 years ago
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