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kipiarov [429]
4 years ago
14

Simplify the square root of 50x^7y^4

Mathematics
1 answer:
Alekssandra [29.7K]4 years ago
6 0
\sqrt{50x^7y^4}=\sqrt{25*2*x^2*x^2*x^2*x*y^2*y^2}=5*x*x*x*y*y*\sqrt{2*x}=5x^3y^2\sqrt{2x}<span>
</span>
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