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pav-90 [236]
3 years ago
13

When 25 is added to a number the result is 59 less than 4 times the number.

Mathematics
2 answers:
marin [14]3 years ago
6 0
X - the number

The expression:
x+25=4x-59

The solution:
x+25=4x-59 \\
x-4x=-59-25 \\
-3x=-84 \\
x=\frac{-84}{-3} \\
x=28

The number is 28.
Vedmedyk [2.9K]3 years ago
3 0
25+x=4x-59 \\ 3x=84 \\ x=28
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82, 62, 95, 81, 89, 51, 72, 56, 97, 98, 79, 85 order from least to greatest find the The median of the lower half of the data an
Studentka2010 [4]

Answer:

The median of the lower half of the data was determined to be 67 while the median of the upper half of the data was determined to be 92.

Step-by-step explanation:

<u>Step 1:  Order from least to greatest</u>

51, 56, 62, 72, 79, 81, 82, 85, 89, 95, 97, 98

<u>Step 2:  Determine the median of the lower half of the data</u>

There are 12 numbers which means that there is going to be 6 numbers on both sides of the data.  So using the first 6 numbers we will be able to determine the median of the lower half of the data.

51, 56, 62, 72, 79, 81

Since there is an even amount of numbers, that means that we will need to find the middle between the 3rd and 4th number.  We can do that by adding them up together and dividing by 2.

(62 + 72) / 2 = 67

Step 3:  <u>Determine the median of the upper half of the data</u>

So using the first 6 numbers we will be able to determine the median of the upper half of the data.

82, 85, 89, 95, 97, 98

Since there is an even amount of numbers, that means that we will need to find the middle between the 3rd and 4th number.  We can do that by adding them up together and dividing by 2.

(89 + 95) / 2 = 92

Answer: The median of the lower half of the data was determined to be 67 while the median of the upper half of the data was determined to be 92.

5 0
2 years ago
If
Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}

Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

5 0
3 years ago
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