Solution:
Given:

Lets First Differentiate the given equation with respect to x



-----------------------(1)
this can be rewritten as

Now differentiating again with respect to x

Now substituting (1) we get



At(1,2) 



Answer:
∠
° or B
Step-by-step explanation:


Answer:
347-+/'3
Step-by-step explanation:
Answer:
X = 1
Step-by-step explanation:
2x^2 + x - 1 = 2
2x^2 + x - 3 = 0
2x^2 + 3x -2x - 3 = 0
x(2x+3) -1 ( 2x+3) = 0
(x-1) (2x+3) = 0
x-1=0
x=1
2x+3=0
2x=-3
x=-3/2.
Answer:2
Step-by-step explanation:
x is located on the horizontal line, so when we look at 3 on the horizontal and trace that line up to where it hits the red line of the function you will find y, the vertical value which is 2