Answer:
Check the explanation
Step-by-step explanation:
in this particular type of problems,we have to go with the cases.we know there would be a 50 odd-even pairs between 1 and 100.
1st case: 1 is placed at the head position of given set S.so there is a chance of only one even number beside 1.so there are 50×98!
2nd case: 1 is placed at tail position of S.so there is again a chance of one even number beside 1. so there are
50×98!
3rd case: 1 is placed neither at head nor at tail.1 can be at rest 98 places.lets fix the place of 1.then the choices are difference between permuting all the numbers and 1 surrounded by two odd numbers.
i.e., 99! - 49p2 ×97!
so total choces are = 2×50×98! + 99! - 49p2 × 97!
= 7448 × 97! + 99!
Answer:
15
Step-by-step explanation:
1.5*10 =15
<span /><span /><span />Algebra Factor 36x^2-81 <span><span>36<span>x2</span>−81</span><span>36<span>x2</span>-81</span></span>
Factor <span>99</span>
out of <span><span><span>36<span>x2</span></span><span>−81</span></span><span><span>36<span>x2</span></span><span>-81</span></span></span>
.Tap for more steps...Factor <span>99</span>
out of <span><span>36<span>x2</span></span><span>36<span>x2</span></span></span>
.
10; you can buy ten cartridges because 140/14 is of course 10. Feedback is appreciated :-)
C because coordinates go like: (x,y) so the y is 6 and C is the only answer with the y as a 6