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Mnenie [13.5K]
3 years ago
6

At a basketball game, a vender sold a combined total of 161 sodas and hot dogs. The number of sodas sold was 43 more than the nu

mber of hot dogs sold. Find the number of sodas sold and the number of hot dogs sold.
Mathematics
1 answer:
Masja [62]3 years ago
5 0
Let s be the soda and h be the hot dogs ,there are two equations here. By the problem s+h =161 s= h+43 ∴2h+43=161 so h=161-43/2 =59 so he sold 59 hot dogs and 59+43 =102 sodas.
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Step-by-step explanation:

We have two shelves, the top shelf s_{t} and the bottom shelf s_{b}.

Now, firstly we are told the top shelf has 10 more than 1/3 the number of books on the bottom shelf. This can be expressed as:

s_{t}=10+\frac{1}{3}s_{b} (1)

Then, we are told there are 12 books on the bottom shelf:

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Substituting (2) in (1):

s_{t}=10+\frac{1}{3}(12) (3)

s_{t}=10+\frac{12}{3} (4)

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