When (-5, 2) is reflected across the y-axis then it becomes (5, 2). When (-5, 2) is reflected across the x-axis, it becomes (-5, -2)
I hope this helps out!
1. Given
2. AD is parallel to BC
3. ∠3 ≅ ∠2
4. transitive property of congruence
5. Definition of bisect
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so
points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)
so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer
That's answer exactly is -5
