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Masteriza [31]
3 years ago
11

You and a friend plan to see 2 movies over the weekend. You can choose from 6 comedy, 2 drama, 4 romance, 1 science fiction, or

3 action movies. You write the movie titles on pieces of paper, place them in a bag, and each randomly select a movie. What is the probability that neither of you selects a comedy? Is this a dependent or independent event? Explain. Please help me..
Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0
There are a total of 16 movies to choose from and 6 of them are comedy. This means that you have a 38% of choosing comedy. But the chances of you not choosing comedy is 62%. And since your friend is also choosing, the chance of neither of you not choosing is cut in half.

So, the final answer of neither of you choosing comedy is 31%

(I don't know whether it's dependent or independent)
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cos(90-\theta)=\frac{BC}{AC} \\\\sin(90-\theta)=\frac{AB}{AC}\\\\tan(90-\theta)=\frac{AB}{BC}

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Learn more on trigonometry here: brainly.com/question/20519838

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The best way to work on them is to start by finding the "portion" of the job done by each of the people in the unit of time.

So, for example, Sarah completes the project in 90 minutes, so in the unit of time (that is 1 minute) she completed 1/90 of the total project

Betty completes the project in 120 minutes, so in the unit of time (1 minute) she completes 1/120 of the total project.

We don't know how long it would take for them to complete the project when working together, so we call that time "x" (our unknown).

Now, when they work together completing the entire job in x minutes, in the unit of time they would have done 1/x of the total project.

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