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3 years ago

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Mr. Wang needs a total of 410 spoons for his son's birthday party. He currently has 278 spoonsIf has 12 spoons, what is the mini

mum number of sets he should buy?

1 answer:

Marina86 [1]3 years ago

6 0

Answer:

Minimum amount of sets needed = 11 sets

Step-by-step explanation:

Total number of needed spoons = 410

Total number of available spoons = 278

Amount needed to be bought = 132 spoons

each set has 12 spoons

Therefore minimum amount of sets needed = 132/12 = 11 sets

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What is the answer to 7/12 plus 1/3

viva [34]

Answer: 11/12

Step-by-step explanation: Notice that 7/12 and 1/3 are unlike fractions. Our first step when adding unlike fractions is to get a common denominator.

The common denominator of 12 and 3 will be the least common multiple of 12 and 3 which is 12.

The fraction 7/12 already has a 12 in the denominator so we leave it alone.

To get a 12 in the denominator of 1/3, we multiply both the numerator and the denominator by 4 and we get the equivalent fraction 4/12.

Now we are adding like fractions.

To add like fractions, we simply add across the numerators.

7/12 + 4/12 = 11/12

Therefore, 7/12 + 1/3 = 11/12.

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Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

TiliK225 [7]

Answer:

$\dfrac{9}{25}$

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }$

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

$P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}$

Now, the <em>required probability</em> can be found as:

$P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }$

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Step-by-step explanation:

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3 years ago

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1. What is the value of the y variable in the solution to the following system of equations?

ollegr [7]

Part 1)

we have

$3x-6y=3$ ------> equation A

$7x-5y=-11$ ------> equation B

Multiply by $-7$ the equation A

$-7(3x-6y)=-7*3$

$-21x+42y=-21$ ------> equation C

Multiply by $3$ the equation B

$3*(7x-5y)=-11*3$

$21x-15y=-33$ -------> equation D

Adds equation C and equation D

$-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2$

therefore

<u>the answer Part 1) is the option A </u>

$y=-2$

Part 2)

we have

$3x+y=6$

$y=-3x+6$ ------> equation A

$6x+2y=8$

Simplify Divide by $2$ both sides

$3x+y=4$

$y=-3x+4$ ------> equation B

the lines A and B are parallel lines, because the slope m is equal

so

The system has no solution

therefore

<u>the answer Part 2) is the option D</u>

There is no x value as there is no solution to the system.

Part 3)

we have

$4x+2y=6$ ------> equation A

$x-y=3$

$y=x-3$ ------> equation B

substitute equation B in equation A

$4x+2[x-3]=6$

$6x-6=6$

$6x=12$

$x=2$

therefore

<u>the answer part 3) is the option D</u>

$x=2$

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

$x+y=1,120$

$x=1,120-y$ -------> equation A

$3x-2y=1,300$ ------> equation B

substitute equation A in equation B

$3[1,120-y]-2y=1,300$

$3,360-5y=1,300$

$5y=3,360-1,300$

$5y=2,060$

$y=412$

therefore

<u>the answer part 4) is the option D</u>

$y=412$

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2 years ago

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