Answer:
<em>Solution; - 4 / t + 1</em>
Step-by-step explanation:
See procedure below;
( 12 - 4t ) / ( t^2 - 2t - 3 ) ⇒ Factor out common term - 4 in 12 - 4t,
- 4 * ( t - 3 ) / ( t^2 - 2t - 3 ) ⇒ Break bottom expression into groups,
- 4 * ( t - 3 ) / ( t^2 + t ) + ( - 3t - 3 ) ⇒ Factor out t from t^2 + t,
- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3t - 3 ) ⇒ Factor out - 3 from - 3t - 3,
- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3 * ( t + 1 ) ) ⇒ Factor out common term t + 1,
- 4 * ( t - 3 ) / ( t + 1 ) * ( t - 3 ) ⇒ Cancel out like term t - 3,
<em>Solution; - 4 / t + 1</em>
The equation
are true for x = -2 and x = 2.
The given equations are given as:

We need to select two equations that are true for x = -2 and x = 2.
<h3>
What are the solutions to an equation ?</h3>
The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.
Example:
x - 2 = 2
Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.
4 - 2 = 2
2 = 2
Let's find the solutions for each equation.
1.

= 4
x =
= ± 2
x = = 2 and x = -2
2.

x = 
x =
= 
x = ± 2
x = 2i and x = -2i where i = 
3.
3
+ 12 = 0
= -12 / 3 = -4
x =
x = ± 2
x = 2i and x = -2i
4.
4
= 16
= 16 / 4
= 4
x = 
x = ±2
x = 2 and x = -2
5.


x - 2 = 0
x = 2.
Thus the equation
have solutions x = -2 and x = 2.
Learn more about solutions of equations here:
brainly.com/question/14506845
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