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Aliun [14]
3 years ago
15

Find X 5x A) 11 C) 2 B) -1 D) -2

Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

the answer is A

Step-by-step explanation:

5x + 78 + 47= 180

solve for x

x=11

Ksivusya [100]3 years ago
4 0

Answer: A) 11

Step-by-step explanation:

there are 180 degrees in a triangle. so, i added 47 and 78 together. that got me 125. i subtracted that from 180, in order to find the remaining angle.

it was 55 degrees, so i divided 55 by 5 in order to see what that was. whatever number that is was going to be x. it turned out to be 11.

hope this helps! xoxo

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What is the simplified form of (12-4t)/(t^2-2t-3)? State any excluded values
nexus9112 [7]

Answer:

<em>Solution; - 4 / t + 1</em>

Step-by-step explanation:

See procedure below;

( 12 - 4t ) / ( t^2 - 2t - 3 ) ⇒ Factor out common term - 4 in 12 - 4t,

- 4 * ( t - 3 ) / ( t^2 - 2t - 3 ) ⇒ Break bottom expression into groups,

- 4 * ( t - 3 ) / ( t^2 + t ) + ( - 3t - 3  ) ⇒ Factor out t from t^2 + t,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3t - 3 ) ⇒ Factor out - 3 from - 3t - 3,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3 * ( t + 1 ) ) ⇒ Factor out common term t + 1,

- 4 * ( t - 3 ) / ( t + 1 ) * ( t - 3 ) ⇒ Cancel out like term t - 3,

<em>Solution; - 4 / t + 1</em>

3 0
3 years ago
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

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2 years ago
Drag the item from the item bank to its corresponding match
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You are converting the numbers to a word problem.

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3. 5x= five times x

4. 5/x= five divided by x

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6. two minus three-fourths of x

7. 3 times x plus 10

8. ten times x plus three
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tiny-mole [99]

Answer:

The slope is 1/2

Step-by-step explanation:

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Answer:

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