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Ratling [72]
3 years ago
8

Please help me and please say all the answers to this it has to be more than 1 answer

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0
I believe the correct answers would be A & C
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Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
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Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

P(X>140)=P(Z>\frac{140-112}{14})

P(X>140)=P(Z>\frac{28}{14})

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The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

P(X>140)=0.0228

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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Two lines and a point are guaranteed to be coplanar If..
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