1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AURORKA [14]
3 years ago
5

10-x=-2x what is it ???

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

x = - 10

Step-by-step explanation:

Given

10 - x = - 2x ( add 2x to both sides )

10 + x = 0 ( subtract 10 from both sides )

x = - 10

You might be interested in
Please help got stuck on this one Thank you
Naya [18.7K]
A. is the correct answer, because you are adding the same numbers as shown in the expression above, however, in a different order
5 0
3 years ago
the population pf a city is 2,500. if the number of males is 240 more than the number of females how many males and females are
Masteriza [31]

You need to represent the number of males in terms of females.

Explanation:

Since you know the number of males relative to females, it makes sense to represent the number of females as a variable, let's say f.

So then the number of males is <span>f+240</span> and we know that the number of males plus the number of females is 2500. Knowing this, we can write an equation: <span>f+<span>(f+240)</span>=2500</span>. I put the number of males in brackets there just to make it easy to recognize.

This equation can be condensed into <span>2f+240=2500</span> and then solved:

<span>2f=2500−240</span>
<span>f=<span><span>2500−240</span>2</span></span>
<span>f=1130</span>

Then, we know the number of females, and we can solve for the number of males from here using our male formula: <span>males=f+240</span>. You should then get 1370 as the number of males.

Checking this answer, we see that 1130 + 1370 does equal 2500.


5 0
4 years ago
Which inequality is a true statement?
tiny-mole [99]

Answer:

It is the second one and the last one.

Step-by-step explanation:

5 0
3 years ago
Make x the subject of the formula<br>6x + a = 5(x + 1)​
kati45 [8]

Answer:

x = 5 - a

Step-by-step explanation:

Given

6x + a = 5(x + 1) ← distribute

6x + a = 5x + 5 ( subtract 5x from both sides )

x + a = 5 ( subtract a from both sides )

x = 5 - a

5 0
3 years ago
Read 2 more answers
Please help!!<br> Write a matrix representing the system of equations
frozen [14]

Answer:

(4, -1, 3)

Step-by-step explanation:

We have the system of equations:

\left\{        \begin{array}{ll}            x+2y+z =5 \\    2x-y+2z=15\\3x+y-z=8        \end{array}    \right.

We can convert this to a matrix. In order to convert a triple system of equations to matrix, we can use the following format:

\begin{bmatrix}x_1& y_1& z_1&c_1\\x_2 & y_2 & z_2&c_2\\x_3&y_2&z_3&c_3 \end{bmatrix}

Importantly, make sure the coefficients of each variable align vertically, and that each equation aligns horizontally.

In order to solve this matrix and the system, we will have to convert this to the reduced row-echelon form, namely:

\begin{bmatrix}1 & 0& 0&x\\0 & 1 & 0&y\\0&0&1&z \end{bmatrix}

Where the (x, y, z) is our solution set.

Reducing:

With our system, we will have the following matrix:

\begin{bmatrix}1 & 2& 1&5\\2 & -1 & 2&15\\3&1&-1&8 \end{bmatrix}

What we should begin by doing is too see how we can change each row to the reduced-form.

Notice that R₁ and R₂ are rather similar. In fact, we can cancel out the 1s in R₂. To do so, we can add R₂ to -2(R₁). This gives us:

\begin{bmatrix}1 & 2& 1&5\\2+(-2) & -1+(-4) & 2+(-2)&15+(-10) \\3&1&-1&8 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\0 & -5 & 0&5 \\3&1&-1&8 \end{bmatrix}

Now, we can multiply R₂ by -1/5. This yields:

\begin{bmatrix}1 & 2& 1&5\\ -\frac{1}{5}(0) & -\frac{1}{5}(-5) & -\frac{1}{5}(0)& -\frac{1}{5}(5) \\3&1&-1&8 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\3&1&-1&8 \end{bmatrix}

From here, we can eliminate the 3 in R₃ by adding it to -3(R₁). This yields:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\3+(-3)&1+(-6)&-1+(-3)&8+(-15) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&-5&-4&-7 \end{bmatrix}

We can eliminate the -5 in R₃ by adding 5(R₂). This yields:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0+(0)&-5+(5)&-4+(0)&-7+(-5) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&0&-4&-12 \end{bmatrix}

We can now reduce R₃ by multiply it by -1/4:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\ -\frac{1}{4}(0)&-\frac{1}{4}(0)&-\frac{1}{4}(-4)&-\frac{1}{4}(-12) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

Finally, we just have to reduce R₁. Let's eliminate the 2 first. We can do that by adding -2(R₂). So:

\begin{bmatrix}1+(0) & 2+(-2)& 1+(0)&5+(-(-2))\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 0& 1&7\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

And finally, we can eliminate the second 1 by adding -(R₃):

\begin{bmatrix}1 +(0)& 0+(0)& 1+(-1)&7+(-3)\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 0& 0&4\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

Therefore, our solution set is (4, -1, 3)

And we're done!

3 0
3 years ago
Other questions:
  • Julia has correctly answered 35 questions from a test, which is 7/12 of the total. How many questions did the test have?
    13·1 answer
  • What is the math paper lesson 68
    11·1 answer
  • What is the radius? Esther &amp; jim plan to add a pond to there property. the area of the pond is 11 square meters. A) 3 B)√3 C
    9·1 answer
  • Can someone help me and don't comment if you don't know the answerer your just taking points from someone who dose know it
    9·1 answer
  • Karl needs to build a stage that has an area of 72 square feet.The length of the stage should be longer than the width.what are
    15·1 answer
  • A culinary club earns $843 from a dinner service. They sold 31 adult meals and 54 student meals. An adult meal costs $8 more tha
    9·1 answer
  • I need help on 11,13,14,15
    7·1 answer
  • Help pls!!!!!!!!!!!
    5·1 answer
  • What value could be added to 2/15 to make the sum greater than 1/2?
    13·1 answer
  • Para encontrar el área de un trapezoide Dylan usa la fórmula A = 1/2(b + b2 )h. Las bases tienen longitudes de 3,6
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!