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suter [353]
3 years ago
12

What is AE ? Enter your answer in the box. ____units

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0

Question says to find AE based on given information in the picture.

We see that AB and CD are parallel lines

AD acts as transversal on AB and CD

then

∠CDE= ∠BAE {alternate interior angles}

similarly

∠DCE= ∠ABE {alternate interior angles}


∠CED= ∠BEA {opposite angles}


so by AAA property of triangles.

Triangle CDE and triangle BAE are similar.

By properties of similar triangles, we know that ratio of corresponding sides is always equal so we can write:

\frac{DE}{AE}=\frac{CD}{BA}

=\frac{x+6}{2x+6}=\frac{8}{10}

10(x+6)=8(2x+6)

10x+60=16x+48

10x-16x=48-60

-6x=-12

x=2

We have to find AE which is 2x+6

AE= 2x+6 = 2*2+6= 4+6 = 10

Hence final answer is AE = 10.


myrzilka [38]3 years ago
3 0
56 units is the answer
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14 trees is less than 640 inches

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An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
Please help me lol a lil confused
alex41 [277]

\leadsto f( \rm x) =  - (x - 3)(x - 5)

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}  - 5x - 3x + 15) \\

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}   - 8x + 15) \\

\\  \\

\leadsto f( \rm x) =   - {x}^{2}  + 8x  -  15 \\

3 0
2 years ago
Read 2 more answers
A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided
bulgar [2K]

Answer:

Length of other board =\frac{4x+20}{x^{2} -4} metres

Step-by-step explanation:

Given: Length of board = \frac{7}{x-2} metres

Length of board was divided into two.

Length of one piece = \frac{3}{x+2} metres

Let l = length of the other board

Length of the other board = Length of board - Length of one piece

So, l=\frac{7}{x-2}-\frac{3}{x+2}

l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}

Thus, length of the other board =\frac{4x+20}{x^{2} -4} metres

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Inverse cosine of square root of 3 over 2? cos-1(square root of 3/2)
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Cos(x°) = (√3)/2
cos⁻¹[(√3)/2] = x°, that means x° = 30°
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