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2 years ago

A principal of $3800 is invested at 6.75% interest, compound annually. How much will the investment worth after 9 years?

Mathematics

1 answer:

frozen [14]2 years ago

6 0

Answer:

$6840.60

Step-by-step explanation:

formula od compound interest A= P (1 =r/n)ⁿ⁹

where n=1 when it is compunded annually and t= 9 years

A= 3800(1+6.75/100)⁹

A= 3800 ( 1+0.0675)⁹

A= 3800(1.0675)⁹

A=3800(1.800)

A= 6,840.60 $

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$\bold{\huge{\pink{\underline{ Solution }}}}$

We have given in the question that, 

The sum of 2 numbers is equal to 11
The difference between two numbers is 19 .

$\bold{\underline{ To \: Find }}$

We have to find the value of x and y.

$\bold{\underline{ Let's \: Begin }}$

Let the two numbers be x and y

According to the question, 

$\sf{ x + y = 11......eq(1) }$

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Solving eq( 1 ) we get :- 

$\sf{ x + y = 11 }$

$\sf{ x = 11 - y ......eq(3 ) }$

Subsituting eq(3 ) in eq(2) :-

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$\sf{\red{Thus ,\: the\: value\: of \: y = -4}}$

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