DGFH is a rhombus where E is the midpoint of the lines GE and GF
please look at the image
<span>f(x)= -2x +1 for f(3)
f(3) = -2(3) + 1 = -5
answer
</span><span>A)-5</span>
Answer:
61
Step-by-step explanation:
Use PEMDAS (Parenthesis first, Exponents second, Division/Multiplication third, Addition/Subtraction last)
(9+2) x 6 - 5
11 x 6 - 5
66 - 5
61
<span>Coffee mug is cylindrical in shape.
So, volume of cylinder = V=π r² h
Mass of coffee = 400 g which is filled to a depth of 8.00 cm. so, h=8.00 cm
density of water = 1 g/cmÂł
Density = mass/volume
1 g/cmÂł = 400g / volume
volume = (400g) / (1 g/cmÂł)
volume = 400 cmÂł
As,
volume of cylinder -
V=π r² h
400 cm³ = π r^2 x 8.00 cm
π r² = (400 cm³) / (8.00 cm)
π r² = 50 cm²
r² = (50)/ π
r² = 15.924 cm²
Taking square root on both sides -
r =3.99 cm
r =4.00 cm
Answer: Thhe inside radius of coffee mug is 4.00 cm</span>
