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Sedbober [7]
4 years ago
14

Plz help i need helppppppp

Mathematics
1 answer:
Goshia [24]4 years ago
8 0

Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

a_1=12 \\  a_n=a_{n-1}+4.

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

a_1=20\\  a_n=a_{n-1} - 5

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

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How do we solve for x
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X/2 + 5 = -10
x/2 = -10 - 5
x/2 = -15
x = -15(2)
x = -30
3 0
3 years ago
At Harry's discount hardware everything is sold for 20 percent less than the price marked. If Harry buys tool kits for $80,what
ICE Princess25 [194]

Answer:

$120.

Step-by-step explanation:

The amount he sells the tool kit for  = 80 + 20% of 80

= 80 + 16

= $96.

Let m be the marked price, then

m - 0.20m = 96

0.8m = 96

m = $120.

5 0
3 years ago
In order to use a ladder safely, the angle that the ladder forms with the ground should not exceed 70 degree. If you have a ladd
solong [7]

Answer:

Maximum safe height can be reached by ladder = 15.03. ft

Step-by-step explanation:

Given,

Let's assume the maximum safe height of wall = h

angle formed between ladder and ground = 70°

length of ladder = 16 ft

From the given data, it can be seen that ladder will form a right angle triangle structure with the wall

So,from the concept of trigonometry,

Sin70^o\ =\ \dfrac{\textrm{maximum safe height of wall}}{\textrm{length of ladder}}

=>Sin70^o\ =\ \dfrac{h}{16\ ft}

=>\ h\ =\ 16\times Sin70^o

=> h = 16 x 0.9396

=> h = 15.03 ft

So, the maximum safe height that can be reached by the ladder will be 15.03 ft.

8 0
3 years ago
Solve the equation x^2-4x+85=0
lara [203]
Can't factor
use quadratic
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
1x^2-4x+85=0
a=1
b=-4
c=85

x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}
x=\frac{4+/- \sqrt{16-340} }{2}
x=\frac{4+/- \sqrt{-324} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}
remember that √-1=i
x=\frac{4+/- i(\sqrt{324}) }{2}
x=\frac{4+/- i(18) }{2}
x=2+/-9i

x=2+9i or x=2-9i
3 0
3 years ago
Find the values for c and d
baherus [9]

Answer:

c=-5

d=1

Step-by-step explanation:

(cy^2)(4y^d)=-20y^3

I'm going to reorder the left-hand side.  Multiplication is commutative.

(4c)(y^2y^d)=-20y^3

Since the bases are the same in y^2y^d and the operation is multiplication, I'm going to add the exponents giving me:

4cy^{2+d}=-20y^3

So this implies we have two equations to solve:

4c=-20 and 2+d=3

So the first equation can be solved by dividing both sides by 4 giving you c=-5.

The second equation can be solved by subtracting 2 on both sides giving you d=1.

6 0
4 years ago
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