9514 1404 393
Answer:
Triangle Angle Sum
Step-by-step explanation:
<em>Corresponding angles</em> applies to parallel lines crossed by a transversal, or to angles in similar figure. The term has no meaning in this geometry.
<em>Supplementary angles</em> refers to a pair of angles that have a sum of 180°. Usually these are seen in quadrilaterals and figures involving parallel lines. The term has no meaning in this geometry.
The Pythagorean theorem relates side lengths in a right triangle. It has no utility in this geometry. Here we're concerned with angles, not sides.
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The theorem useful for finding x is the Triangle Angle Sum theorem, which tells you the sum of angles in a triangle is 180°. That theorem lets you write a linear equation involving x, so that x can be found.
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(3x -2) +(x +8) +(2x +3) = 180
6x +9 = 180
x = 171/6 = 28.5°
The three angles are 36.5°, 60°, 83.5°.
By placing it on the corner or the origin in the middle extremity/point or you can use it on a vertex, on the angel that you're working with.
Answer:
Step-by-step explanation:
Given: 
To convert: the given sum into product
Solution:
Use formula: 
![cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]](https://tex.z-dn.net/?f=cosx%20%2B%20cos3x%20%2B%20cos5x%20%2B%20cos7x%3D2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx%2B3x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx-3x%7D%7B2%7D%20%5Cright%20%29%2B2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x%2B7x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x-7x%7D%7B2%7D%20%5Cright%20%29%5C%5C%3D2%5Ccos%20%282x%29%5Ccos%20%28-x%29%2B2%5Ccos%20%286x%29%5Ccos%20%28-x%29%5C%5C%3D2%5Ccos%20%282x%29%5Ccos%20%28x%29%2B2%5Ccos%20%286x%29%5Ccos%20%28x%29%5C%5C%3D2%5Ccos%20x%5Cleft%20%5B%20%5Ccos%20%282x%29%2B%5Ccos%20%286x%29%20%5Cright%20%5D)
![cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)](https://tex.z-dn.net/?f=cosx%20%2B%20cos3x%20%2B%20cos5x%20%2B%20cos7x%3D2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx%2B3x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx-3x%7D%7B2%7D%20%5Cright%20%29%2B2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x%2B7x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x-7x%7D%7B2%7D%20%5Cright%20%29%5C%5C%3D2%5Ccos%20x%5Cleft%20%5B%20%5Ccos%20%282x%29%2B%5Ccos%20%286x%29%20%5Cright%20%5D%5C%5C%3D2%5Ccos%20x%5Cleft%20%5B2%20%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B2x%2B6x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B2x-6x%7D%7B2%7D%20%5Cright%20%29%20%5Cright%20%5D%5C%5C%3D2%5Ccos%20x%5Cleft%20%5B%202%5Ccos%20%284x%29%20%5Ccos%20%28-2x%29%20%5Cright%20%5D%5C%5C%3D4%5Ccos%20x%5Ccos%20%284x%29%5Ccos%20%282x%29)
The equation has infinite many solutions
<h3>How to determine the number of solutions?</h3>
The equation is given as:
12x + 1 = 3(4x + 1) - 2
Open the brackets
12x + 1 = 12x + 3 - 2
Evaluate the like terms
12x + 1 = 12x + 1
Both sides of the equation are the same
This means that the equation has infinite many solutions
Read more about equation solutions at:
brainly.com/question/13729904
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