Answer:
i think ii first add 5x + x then you can remove the parentheses, group similar terms and add similar elements
Step-by-step explanation:
Answer:
You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.
The probability of selecting a red marble the first time is 1313.
(This is because 4 out of 12 marbles are red and412412 reduces to 1313.
The probability of selecting a red marble the second time is 1313.
The marble selections are independent and you can multiply the two probabilities to get the following:
probability of getting 2 reds = (13)2(13)2
=19=19.
So the probability of getting two reds is 1919.
Answer:
0.25k + 1.5 - k - 3.5 = -0.75k - 2.
Step-by-step explanation:
Answer: 40,320
Step-by-step explanation: Let's say that there is person A,B,C,D,E,F,G,H. and 8 chairs. For the first chair, 8 different people could potentially sit in it, making 8 different possibilities. No matter who sits there, the logic follows the next table. However, since one person is sitting in the first chair, there are 7 different possibilities about who would be sitting in the second chair. If you multiply the two together, there are 56 different possibilities just for the first and second chair. For the third chair, there are 6 different possibilities about whom could sit. Multiply 56*6 and you get 336 possibilities. Keep multiplying out and you get a grand total of 40,320 different arrangements!
Answer:
Perimeter of rectangle before folded = 56 in
Total area after folding = 156 sq in
Step-by-step explanation:
Rectangle before folded: l = 16 and w = 12
P = 2(16) + 2(12) = 32 + 24 = 56 in.
Figure after folding: Area of trapezoid + area of rectangle
Area of trapezoid = h(
)/2 = 6(4 + 16)/2 = 60
Area of rectangle = lw = 16(6) = 96
Total area after folding = 60 + 96 = 156 sq in.
Note: You could also find the area after folding by substracting the areas of the two triangles in the corners from the area of the original rectangle. Your choice. OK?
