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3 years ago

Evaluate the expression. 24 ÷ 2 - 6 + 8 ÷ 2

Mathematics

2 answers:

arlik [135]3 years ago

6 0

The answer of this expression is 10

vovangra [49]3 years ago

5 0

24 / 2 = 12
8/2=4
12-6= 6
6+4= 10

Final answer is 10

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The function after synthetic division f(x) = 4x3 + 3x2 − 16x − 12

Georgia [21]

Answer:

$\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}$

»ANSWER«

(1) Write properties of function:

x intercept/zero:

$x_{1} = \frac{3}{4}$

y intercept:

$y = - 12$

domain:

$( - \infty \: \infty )$

type of function: cubic fraction

standard form:

$f(x) = 4 {x}^{3} - 3 {x}^{2} + 16x - 12$

factorize form:

$f(x) = (4x - 3)( {x}^{2} + 4)$

even/odd/neither: neither

bounce/cross x axis:

$x = \frac{3}{4} \: across$

increasing interval:

$( - \infty \: \infty )$

decreasing interval: no

number of positive real zeros: 1

number of possible turning point: 2

order/degree: 3

leading term:

$4x ^{3}$

leading coefficent: 4

constant term: -12

end behavior:

$as \: x \: → \infty f(x) → \infty \: as \: x → - \infty f(x) → - \infty$

#CarryOnLearning

8 0

2 years ago

What angle is this?

FromTheMoon [43]

Corresponding angles

5 0

3 years ago

Find the value of x<br><br> plz help

solong [7]

Answer:

x=19

Step-by-step explanation:

82+79=161

180-161=19

7 0

2 years ago

A 11 gram sample of a substance that’s used to treat thyroid disorders has a k- value of 0.125

NikAS [45]

The substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

<h3>What is exponential decay?</h3>

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an exponential function:

$\rm N = N_oe^{-kt}$

Plug N = N⁰/2

$\rm N_o/2 = N_oe^{-kt}$

$\rm \dfrac{1}{2} = e^{-0.125t}$

Solving for t:

t = 5.54 ≈ 5.5 days

Thus, the substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

Learn more about exponential decay here:

brainly.com/question/14355665

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