It has one X-intercept. Graph it on Desmos and you can see the line, and then it becomes obvious it is one x-intercept.
Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
Than you multiplie tha 50 by 1/50 so will get 50/50 what is equal 1
hope this is understandably sure right easy
7 - 2 (7) -8
7 - 14 - 8
7-14= -7
-7 - 8 = - 15
May have messed this one up
