Question

Can anyone help me solve 23, 24?

Answer 1

Answer:

Problem 23) $y=3x+6$

Problem 24) $y=-\frac{1}{3}x-5$

Step-by-step explanation:

step 1

Find the slope of the given line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$A(0,2)\ B(3,1)$

Substitute the values

$m=\frac{1-2}{3-0}$

$m=-\frac{1}{3}$

step 2

Problem 23

we know that

If two lines are perpendicular then the product of its slopes is equal to minus 1

so

$m1*m2=-1$

Find the slope of the line

we have

$m1=-\frac{1}{3}$

substitute in the equation and solve for m2

$(-\frac{1}{3})*m2=-1$

$m2=3$

with the slope m2 and the point $(0,6)$ find the equation of the line

Remember that

The equation of the line in slope intercept form is equal to

$y=mx+b$

we have

$m=3$

$b=6$ -----> the given point is the y-intercept

substitute

$y=3x+6$

step 3

Problem 24

we know that

If two lines are parallel, then its slopes are the same

so

with the slope m1 and the point $(0,-5)$ find the equation of the line

The equation of the line in slope intercept form is equal to

$y=mx+b$

we have

$m=-\frac{1}{3}$

$b=-5$ -----> the given point is the y-intercept

substitute

$y=-\frac{1}{3}x-5$