Please help, I don’t understand this. Will give brainliest

A translation moves point V(–2, 3) to v'(-2, 7). Which are true statements about the translation? Check all that apply.

jeka94

The answer is B) The transformation rule is (x, y) -> (x + 0, y + 4).

7 0

3 years ago

Read 2 more answers

6. (5y+2)+14x=5y+ (2+14x)

svetoff [14.1K]

In my opinion it is C

4 0

3 years ago

Read 2 more answers

N Example 3, the points are(0,3500) and (5,1750). Write an equation that represents the distance y (in feet) remaining after x m

Cerrena [4.2K]

Answer:

<h2>The time needed is 10 months.</h2>

Step-by-step explanation:

The given points are (0, 3500) and (5, 1750).

First, we use the formula below to find the slope of the line

$m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }=\frac{1750-3500}{5-0}=\frac{-1750}{5}=-350$

Which means the function is deacrasing with a ratio of 350 feet per month.

Now, we use the slope and one point to find the equation

$y-y_{1} =m(x-x_{1} )\\y-1750=-350(x-5)\\y=-350x+1750+1750\\y=-350x+3500$

This linear function shows that the situation started at the y-intecept (0, 3500), which means the month 0 had already 3500 feet. In other words, the total distance is 3500 feet. Now, the x-intercept will tell us the time needed to travel that distance.

$0=-350x+3500\\-3500=-350x\\x=\frac{-3500}{-350}\\ x=10$

Therefore, the time needed is 10 months.

3 0

3 years ago

Math again yay!...Ew math

Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

$f(x)=x^2$

New function:

$g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2$

Transformations:

For a > 0

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}$

$\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}$