I put 80 POINTS into question please answer
2 answers:
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Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of .
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:
Where is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is . The critical points of the function are those who make
:
The critical value inside the interval is .
The second step is to find the values of the function at the endpoints of the interval:
The biggest value of f is gived by , therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of .