How to Factor 6y2−24y+186y2−24y+18???

What is the difference :8/7-1/3 -31/21 --7/4 -17/21 -4/7

Tema [17]

8/7-1/3

Make both fractions have the same common denominator

24/21 - 7/21

Subtract the numerators while keeping the denominator the same

Final Answer: C. 17/21

7 0

3 years ago

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Production managers on an assembly line must monitor the output to be sure that the level of defective products remains small. T

lisabon 2012 [21]

Answer:

Factory owners would consider the Type I error worse, because the assembly process will be halted while it shouldn't have been and thus they will lose money.

8 0

3 years ago

A salad dressing recipe requires at least 8 oz of oil to be combined with some combination of vinegar and lemon juice in a 16 oz

valentina_108 [34]

Let x represent the number of ounces of vinegar

Let y represent the number of ounces of lemon juice

Oil required = 8 oz

Container can hold = 16 oz

So the inequality equation will be :

$x+y+8\geq16$

6 0

3 years ago

Solve this equation 18 = n -18 n=

Mandarinka [93]

Answer:

n= 36

Step-by-step explanation:

18=n-18 (add 18 to both sides of the equation, 18 and -18 cancel out)

36=n

8 0

2 years ago

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Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago