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3 years ago

Is .01 less than .07

2 answers:

6 0

No, .07 would represent a bigger number if it were coins it would be .06 more pennies. The only time .01 would be greater then .07 is if it were negative

Amanda [17]3 years ago

5 0

Yes, 0.01 is father from 1 in comparison to 0.07

You might be interested in

8× what =2

sergejj [24]

Answer:

8*1/4= 2

A) 0.071

B) 0.48

5 0

3 years ago

Determine if the graph is a function then state the domain and range.

nignag [31]

<h3>Explanation</h3>

A function is a set of relation that doesn't have repetitive domain. If we want to know if a graph is function or not, we have to do the line test.

Line Test

Draw a vertical line. Make sure that a line passes through a graph.
See if a line intercepts a graph more than one point or just only one.

Result

If a line intercepts a graph more than one point, it is not a function.

However, if a line only intercepts a graph just one point, it is indeed a function.

The given graph from the question is a function because it passes line test.

Domain and Range

Domain is the set of all x-values, meaning we only focus on x-axis or x-value only.

Range is the set of all y-values. We only focus on y-value or y-axis for Range.

Determine Domain from Graph

We can simply say that the domain is from starting domain or x-coordinate point to end x-coordinate point. For example, if a graph starts at x = -4 and ends at x = 2, we can say that - 4<=x=2.

Determine Range from Graph

Similar to Domain except Range starts from the minimum value or point to the maximum point or value. For example if a graph starts at min point = 6 and max point = 9. We can say that 6<=y<=9.

From the graph, the domain starts from negative infinity to positive infinity. Meaning that x can be any numbers. Hence, the domain is set of all real numbers. For range, the minimum value is 0 and max value is positive infinity. Therefore we write y>=0.

<h3>Answer</h3>

 $\begin{cases} x \in \mathbb{R} \\ y \geqslant 0 \end{cases}$ 

Domain is set of all real numbers.

Range is greater or equal to 0.

8 0

3 years ago

What are the coordinates of the midpoint between A(−3, −5) and B(2, 7) ?

natka813 [3]

Use X1+X2 / 2, Y1+Y2 / 2
-3 + 2 / 2 , -5 + 7 / 2
-1 / 2 , 2/2
(-1/2, 1)

I think this is correct... I know you use the top formula

4 0

3 years ago

Explain how finding 7x20 is similar to finding 7 x 2,000. Then find each product

Sphinxa [80]

7×20 and 7×2000 are similar. The amount of zeros are the dependent factor.

7×20= 140
7×2000= 14000

The base equation is 7×2=14
Any additions of zeroes in this formula will be added at the end result.

Ex.
7×2=14
7×20=140
7×200=1400
70×200=14000
700×200=140000

5 0

3 years ago

Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal

tigry1 [53]

Answer:

0.0314 = 3.14% probability that it takes at most 1 hour of machining time to produce a randomly selected component

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Sum of normal variables:

When normal variables are added, the mean is the sum of the means while the standard deviation is the square root of the sum of the variances.

The mean values are 20, 15, and 30 min, respectively:

This means that $\mu = 20 + 15 + 30 = 65$

The standard deviations are 1, 2, and 1.5 min, respectively.

This means that $\sigma = \sqrt{1^2 + 2^2 + 1.5^2} = 2.6926$

What is the probability that it takes at most 1 hour of machining time to produce a randomly selected component?

Mean and standard deviation are in minutes, so this is the pvalue of Z when X = 60.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 65}{2.6926}$

$Z = -1.86$

$Z = -1.86$ has a pvalue of 0.0314

0.0314 = 3.14% probability that it takes at most 1 hour of machining time to produce a randomly selected component

7 0

3 years ago