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ra1l [238]
3 years ago
12

the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base​

Mathematics
1 answer:
wel3 years ago
5 0

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

The breadth of cuboid = b cm

The height of cuboid = h cm

<u>According to question</u>

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 =  2 ×(l × b + b × h + h × l)

Or,  (l × b + b × h + h × l) = \dfrac{95}{2}          ....1

<u>Similarly</u>

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = \dfrac{63}{2}              ......2

Putting value of eq 2 into eq 1

so,  (l × b +  \dfrac{63}{2} ) = \dfrac{95}{2}    

Or, l × b = \dfrac{95}{2} - \dfrac{63}{2}    

Or,  l × b = \dfrac{95 - 63}{2}

i.e l × b = \dfrac{32}{2}

so, l × b = 16

<u>Now, Again</u>

∵The Area of the base = ( length × breadth ) cm²

So, z =  l × b

i.e z = 16 cm²

So, The Area of the base = z = 16 cm²

Hence,The Area of the base is 16 cm² . Answer

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<h3>Volume:</h3>

With this prism, first separate it into a rectangular prism and a right triangle prism.

First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3

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<em>So, within each of these right </em>trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:

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