Answer:
![\left[\begin{array}{cc}2&8\\5&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%268%5C%5C5%261%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The <em>transpose of a matrix </em>
is one where you swap the column and row index for every entry of some original matrix
. Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation
and
to refer to the entry in the i-th row and the j-th column of the matrices
and
respectively:

Constructing the matrix
from those entries gives us
![P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]](https://tex.z-dn.net/?f=P%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%268%5C%5C5%261%5Cend%7Barray%7D%5Cright%5D)
which is option a. from the list.
Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!
I believe the correct answer is B. :)
Answer:
The relation for the distance cover by Tina and Lia is 20 = 4 × m
Option B
Step-by-step explanation
Given as :
The distance cover by Tina =
= 20 miles
The distance cover by Lia =
= m miles
According to question
Tina walked 4 times as far as Lia
So, The distance cover by Tina = 4 × The distance cover by Lia
Or,
= 4 ×
I.e 20 miles = 4 × m miles
or. 20 = 4 × m
So, relation is 20 = 4 × m
Hence, The relation for the distance cover by Tina and Lia is 20 = 4 × m
I.e option B Answer