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oksian1 [2.3K]
3 years ago
14

If 3x + 11 = 4x - 5, what is x?

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0
3x + 11 = 4x - 5
First put the same variables on one side and remember to switch their signs
3x - 4x = -5 - 11
-1 x = -16
x = -16/-1
x = 16
Andrew [12]3 years ago
4 0

Answer:

16v

Step-by-step explanation:

3x + 11 = 4x - 5

11+5 = 4x -3x

x = 16

I hope im right!!

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State of the two triangles are congruent
Murljashka [212]

Answer:

ans:

5. Hl

6. Hl

7. ASA

8. AAS

Step-by-step explanation:

use different axiom for congurency

  1. SAS
  2. RHS
  3. AAS
  4. SSA
  5. ASA
  6. SSS

7 0
3 years ago
S
Nina [5.8K]

Answer:

(2,2)

Step-by-step explanation:

Domain of this function

7 0
2 years ago
The lesson is 19.2 Angles in inscribed Quadrilaterals
alexdok [17]

Answer:

m<R=44.9,m<S=56.9,m<T=44.9,m<U= 32.9.

Step-by-step explanation:

When two chords are equal then the measure of the arcs are equal.

Chord RU= Chord UT

Or , m arc RU= m arc UT,

3z-4=x+2z+7   Or             z=x+11

Chord RS=Chord ST ,

m arc RS=m arc ST=3x+5

Sum of m arc in a circle =360 degrees.

Or ,

3x+5+3x+5+3z-4+x+2z+7=360

7x+5z+13=360

Substituting z=x+11

7x+5(x+11)+13=360

7x+5x+55+13=360

12x+68=360

12x=292,x=24.3

z=x+11=11+24.3=34.3

m arc RU=marc UT= 3z-4=3(24.3)-4=69

m arc RS =marc ST= 3x+5=3(24..3)+5=77.9

m<R= (marc UT+ m  arc ST)÷2

m<R=(69+77.9)÷2=73.45

m<S= (m arc RU+m arc UT)÷2

m<S= (69+69)÷2=69

m<T=(m arc RU+m arc RS)÷2=73.45

m<U=(m arc RS+m arc m arc ST)÷2=77.9








4 0
4 years ago
What is the volume of a regular pyramid whose base has an area of 36 ft? and whose height is 13 ft?
Lesechka [4]

Answer:

Volume of regular pyramid = 156 ft²

Step-by-step explanation:

Given:

Area of regular pyramid = 36 ft²

Height of regular pyramid = 13 ft

Find:

Volume of regular pyramid

Computation:

Volume of regular pyramid = [1/3][b][h]

Volume of regular pyramid = [1/3][36][13]

Volume of regular pyramid = [12][13]

Volume of regular pyramid = 156 ft²

4 0
3 years ago
A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.
Kobotan [32]

Answer:

The numbers are

-2+3\sqrt{5}   and 3\sqrt{5}

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

so

x=y-2

y=x+2 ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

so

4y+x^2=49 ----> equation B

substitute equation A in equation B

4(x+2)+x^2=49

solve for x

x^2+4x-41=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
4 years ago
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