Answer:
420 unique combinations.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
One object from each set:
2 from one set, 5, 6 and 7 by others. Sets are independent, so, by the fundamental counting principle:
2*5*6*7 = 10*42 = 420
420 unique combinations.
you would change the denominators to the least common multiple, in this case, 12. then you would change the fractions to 8/12, 14/12, and 7/12. you would add those, and get 29/12. divide 29 by 12, and get 2. add the rest to get 2 5/12.
Answer:


let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.
here ,

now ,
we just have to plug in the values considering certain other things given in the question and we're done!
so let's start ~

hence , proved ~
hope helpful :D
The answer to question #5 is 17