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Cerrena [4.2K]
3 years ago
8

A milkshake recipe calls for 1/3 cup of milk for each milkshake. If a server has 15/8 cups of milk, what is the maximum number o

f
milkshakes the server can make following the recipe porpotians?​
Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

5 milk shakes

Step-by-step explanation:

From the above question, we know that for the recipe

1/3 cup of milk = 1 milk shake

15/8 cup of milk = y milk shakes

We cross Multiply

15/8 cup × 1 = 1/3cup × y

y = 15/8 cup × 1 /1/3cup

= 15/8 ÷ 1/3

= 15/8 × 3

= 45/8

= 5.625 of 5 5/8 cups of milk

Therefore, the maximum number of

milkshakes the server can make following the recipe porpotians is 5 milk shakes.

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MariettaO [177]
Oh, I SEE what da pattern is! =D
You see, like in this problem:
2 + 5 = 12
They did 5 times 2 = 10, plus da 2 in da problem = 12.
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SO,
with that strategy, 8 +11 = 96, because 8 times 11 = 88, plus da 8 given in da problem = 96.
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