You need a graph to go with it
In triangle, ABD,
AD²= AB²+BD²
AB² = AD²-BD²
AB² = 18²-9² = 324-81 = 243
AB = √243
In triangle, ABC,
AC² = AB²+BC²
AC² = (√243)²+(13)²
AC² = 243+169
AC = √412
AC = 20.29
The unit rate is 5cm per 1min
5:1
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
