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USPshnik [31]
3 years ago
8

The numbers 4, 5, 6, and 7 are on a spinner. You spin the spinner twice. Which calculation proves that landing on an even number

for the first spin and the second spin are independent events?
Mathematics
2 answers:
den301095 [7]3 years ago
7 0

Answer:

As long as the numbers are in equal proportion on the spinner, the probabilty of landing on an even number for the first and second spin is 1/4, or 25%.  

Step-by-step explanation:

If there are four numbers on a spinner, all in equal proportion, than the probability of getting an even number (either 4 or 6) on any spin is 2/4, or 1/2, which is also 50%.  Since the results of the first spin do not influence the results of the second spin, then they are independent events.  So, if the likelihood of landing on even each time is 1/2, then we would mutliply 1/2 by 1/2 in order to find the probability that landing on an even number would happen in both spins.  Our result would be 1/4, or 25%.  

Andreyy893 years ago
5 0

Not sure what that dude is even saying. The answer is C- P(A and B)=2/4*2/4

Hope this helped.


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