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Lelu [443]
3 years ago
5

Please help with finding limits of multi variable calculus!!!

Mathematics
1 answer:
anastassius [24]3 years ago
3 0

To start, let's find the value of x as it gets closer to 0 from the positive side (we are working on the first example). To start, when x is 1, we have sin(2) - 2. This is approximately -1.965. Now, plugging in 2, we get (sin(4)-4)/8. This is -0.491. Now, we plug in 1/2 to get 8sin(1) - 8. This is approximately -7.86. Plugging in something like 1/1000, we will get -1965. Notice that there is no limit to it, so the answer is negative infinity, or DNE (IDK)

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