Question

A board of length 16 ¾ inches is cut into 4 equal pieces. If 7/8 of an inch is then removed from one of these pieces, what is the length of that piece?

Answer 1

Answer: $\dfrac{53}{16}\ \text{or}\ 3\dfrac{5}{16}$

Step-by-step explanation:

Given

Length of board is $16\ \frac{3}{4}$

It is divided into 4 equal pieces i.e. length of each piece is

$\Rightarrow \dfrac{\frac{64+3}{4}}{4}=\dfrac{67}{16}\ \text{in.}$

If  $\frac{7}{8}$ of an inch is removed from one of the pieces then,

$\Rightarrow \dfrac{67}{16}-\dfrac{7}{8}\\\\\Rightarrow \dfrac{67}{16}-\dfrac{14}{16}=\dfrac{53}{16}\ \text{inch}$